All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 94708 by abony1303 last updated on 20/May/20
Commented by abony1303 last updated on 20/May/20
I′msotiredseeingthesetypeofproblemsinmyexam.Cansmnexplainthesekindofquestionsineasyway?Orsuggestmethebooktogetinformation.pls.
Answered by Worm_Tail last updated on 14/Jul/20
Sn=2+2+4+4+4+4+6+6+6+6+6+6+...+n+n+nSn=2(2)+4(4)+6(6)+...+2n(2n)Sn=∑nr=12r(2r)⇒Sn=∑nr=14r2Sn=4Σr2⇒Sn=4n(n+1)(2n+1)6=2(2019)(2020)(4039)3=2(2019)(4039)3(2020)S201910=2(2019)(4039)3(202)remainder0
Terms of Service
Privacy Policy
Contact: info@tinkutara.com