solution: Q1)a) n=((ln(m/m_0 ))/(ln0.5)) = ((ln(12/75))/(ln0.5)) =2.64 N=N_0 (0.5)^n = 6.02×10^(23) (0.5)^(2.64) = 9.66×10^(22) A=λN=1.5×10^(−4) × 9.66×10^(22) =1.45×10^(19) Bq


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Question Number 94756 by AshrafNejem last updated on 20/May/20

$s o l u t i o n : Q 1) a) n = \frac{l n (m / m_{0})}{l n 0.5} = \frac{l n (12 / 75)}{l n 0.5} = 2.64$ $N = N_{0} {(0.5)}^{n} = 6.02 \times 10^{23} {(0.5)}^{2.64} = 9.66 \times 10^{22}$ $A = λ N = 1.5 \times 10^{- 4} \times 9.66 \times 10^{22} = 1.45 \times 10^{19} B q$
Commented by mr W last updated on 20/May/20

$m a y b e o n l y y o u k n o w f o r w h i c h$ $q u e s t i o n y o u r a n s w e r i s . t h e r e f o r e$ $p l e a s e p o s t y o u r a n s w e r i n t h e s a m e$ $t h r e a d a s t h e q u e s t i o n .$
Commented by MJS last updated on 20/May/20

$o tempora o mores$
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