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Question Number 94780 by Abdulrahman last updated on 20/May/20

$$\mathrm{x}!(\mathrm{x}-4)!=12(2\mathrm{x}-7)!$$$$\mathrm{x}=?$$

Commented by MJS last updated on 21/May/20

$$x⩾4$$$$\mathrm{trying}$$$$4!0!>12\times 1!$$$$5!1!>12\times 3!$$$$6!2!=12\times 5!$$$$7!3!<12\times 7!$$$$\Rightarrow x=6$$

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