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Question Number 94910 by mathocean1 last updated on 21/May/20
Solvein[0;2π]2sin(4x−π6)⩾1Pleasesirs...
Answered by mr W last updated on 21/May/20
sin(4x−π6)⩾122kπ+π6⩽4x−π6⩽2kπ+π−π6⇒kπ2+π12⩽x⩽kπ2+π4withk∈Zwithin[0,2π]:π12⩽x⩽π47π12⩽x⩽3π413π12⩽x⩽5π49π12⩽x⩽7π4
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