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Question Number 94960 by bshahid010@gmail.com last updated on 22/May/20

Answered by Kunal12588 last updated on 22/May/20

2+(n−1)(3)=2+(n_1 −1)(5) ⇒3n−1=5n_1 −3 ⇒5n_1 −3n=2 n_1 =1+3t n=1+5t ((n),(n_1 ) ) = ((1,6,(11),(16)),(1,4,7,(10)) ) 4 common terms

2+(n−1)(3)=2+(n1−1)(5)⇒3n−1=5n1−3⇒5n1−3n=2n1=1+3tn=1+5t(nn1)=(16111614710)4commonterms

Answered by mr W last updated on 22/May/20

A_n =2+3n=2+3×5m≤59 B_k =2+5k=2+5×3m≤59 m≤((59−2)/(3×5))=3.8 ⇒0≤m≤3 ⇒4 common terms: 2, 17, 32, 47

An=2+3n=2+3×5m⩽59Bk=2+5k=2+5×3m⩽59m⩽59−23×5=3.8⇒0⩽m⩽3⇒4commonterms:2,17,32,47

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