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Question Number 95009 by bobhans last updated on 22/May/20

∫  ((e^x +2xe^x sin x−2xe^x cos x)/((√x) sin^2 x)) dx

$$\int\:\:\frac{{e}^{{x}} +\mathrm{2}{xe}^{{x}} \mathrm{sin}\:{x}−\mathrm{2}{xe}^{{x}} \mathrm{cos}\:{x}}{\sqrt{{x}}\:\mathrm{sin}\:^{\mathrm{2}} {x}}\:{dx}\: \\ $$

Commented by bobhans last updated on 22/May/20

my children exam

Commented by  M±th+et+s last updated on 22/May/20

think that its  ∫((e^x sin(x)+2xe^x sin(x)−2xe^x cos(x))/((√x)sin^2 (x)))dx

$${think}\:{that}\:{its} \\ $$$$\int\frac{{e}^{{x}} {sin}\left({x}\right)+\mathrm{2}{xe}^{{x}} {sin}\left({x}\right)−\mathrm{2}{xe}^{{x}} {cos}\left({x}\right)}{\sqrt{{x}}{sin}^{\mathrm{2}} \left({x}\right)}{dx} \\ $$

Commented by bobhans last updated on 23/May/20

yes. if ∫ ((e^x sin (x)−2xe^x sin (x)−2xe^x cos (x))/((√x) sin^2 (x))) dx   can be solved .   ∫ (d/dx) [((2(√x) e^x )/(sin (x))) ] = ((2(√x) e^x )/(sin (x))) + c

$$\mathrm{yes}.\:\mathrm{if}\:\int\:\frac{\mathrm{e}^{\mathrm{x}} \mathrm{sin}\:\left(\mathrm{x}\right)−\mathrm{2xe}^{\mathrm{x}} \mathrm{sin}\:\left(\mathrm{x}\right)−\mathrm{2xe}^{\mathrm{x}} \mathrm{cos}\:\left(\mathrm{x}\right)}{\sqrt{\mathrm{x}}\:\mathrm{sin}\:^{\mathrm{2}} \left(\mathrm{x}\right)}\:\mathrm{dx}\: \\ $$$$\mathrm{can}\:\mathrm{be}\:\mathrm{solved}\:.\: \\ $$$$\int\:\frac{\mathrm{d}}{\mathrm{dx}}\:\left[\frac{\mathrm{2}\sqrt{\mathrm{x}}\:\mathrm{e}^{\mathrm{x}} }{\mathrm{sin}\:\left(\mathrm{x}\right)}\:\right]\:=\:\frac{\mathrm{2}\sqrt{\mathrm{x}}\:\mathrm{e}^{\mathrm{x}} }{\mathrm{sin}\:\left(\mathrm{x}\right)}\:+\:\mathrm{c}\: \\ $$

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