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Question Number 95294 by i jagooll last updated on 24/May/20

$$3\mathrm{men},4\mathrm{women}\mathrm{\&}6\mathrm{boy}\mathrm{together}$$ $$\mathrm{working}\mathrm{a}\mathrm{job}\mathrm{within}25\mathrm{day}.\mathrm{if}2\mathrm{men}$$ $$,3\mathrm{women}\mathrm{and}4\mathrm{boy}\mathrm{working}\mathrm{the}$$ $$\mathrm{same}\mathrm{job},\mathrm{complete}\mathrm{in}?$$

Commented bymr W last updated on 24/May/20

$$wecannotdetermine,becausewith$$ $$thegivenconditionwe{can}^{\prime }tknow$$ $$theworkingrateof2men,3women$$ $$and4boys.$$

Commented byPRITHWISH SEN 2 last updated on 24/May/20

$$\mathrm{let}2\mathbf{m}+3\mathbf{w}+4\mathbf{b}=\mathbf{x}...\left(\mathrm{i}\right)$$ $$\mathrm{and}\mathrm{we}\mathrm{get}$$ $$3\mathrm{m}+4\mathrm{w}+6\mathrm{b}=25\Rightarrow 75\mathrm{m}+100\mathrm{w}+150\mathrm{b}=1$$ $$\Rightarrow \frac{75}{\mathrm{x}}\mathrm{m}+\frac{100}{\mathrm{x}}\mathrm{w}+\frac{150}{\mathrm{x}}\mathrm{b}=\mathrm{x}....\left(\mathrm{ii}\right)$$ $$\mathrm{now}\mathrm{compairing}\left(\mathrm{i}\right)\mathrm{\&}\left(\mathrm{ii}\right)\mathrm{we}\mathrm{get}$$ $$\frac{75}{\mathrm{x}}=2\Rightarrow \mathbf{x}=\frac{75}{2}$$ $$\frac{100}{\mathbf{x}}=3\Rightarrow \mathbf{x}=\frac{100}{3}$$ $$\frac{150}{\mathbf{x}}=4\Rightarrow \mathbf{x}=\frac{75}{2}$$ $$\mathbf{so}\mathbf{the}\mathbf{question}\mathbf{is}\mathbf{inconsistent}\mathbf{there}\mathbf{is}\mathbf{something}$$ $$\mathbf{wrong}\mathbf{with}\mathbf{the}\mathbf{question}.\mathbf{I}{\mathbf{don}}^{\prime }\mathbf{t}\mathbf{think}\mathbf{it}\mathbf{is}$$ $$\mathbf{solvable}.$$

Answered by bobhans last updated on 24/May/20

$$\frac{1}{x}=\frac{\frac{2}{3}+\frac{3}{4}+\frac{4}{6}}{25}\Rightarrow x=\frac{25}{\frac{2}{3}+\frac{3}{4}+\frac{2}{3}}$$ $$x=\frac{25}{\frac{4}{3}+\frac{3}{4}}=\frac{25\times 12}{16+9}=12days$$

Commented bybobhans last updated on 24/May/20

$$\mathrm{please}\mathrm{check}$$

Commented bymr W last updated on 24/May/20

$$cannotbecorrect!withmorepeople$$ $$inthepastweneeded25days,now$$ $$wehavelesspeopleandweneedeven$$ $$lesstimethanbefore?$$

Commented bybobhans last updated on 24/May/20

$$\mathrm{this}\mathrm{means}\mathrm{the}\mathrm{problem}\mathrm{is}\mathrm{not}\mathrm{complete}?$$ $$\mathrm{really}?$$

Commented bymr W last updated on 24/May/20

$$correct,{it}^{\prime }snotsolvablewithgiven$$ $$info.$$

Commented byi jagooll last updated on 24/May/20

ok sir. thank you for the discussion

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