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Question Number 95309 by i jagooll last updated on 24/May/20
ify=[2x+5]=3[x−4]then[3x+y]=?
Answered by mr W last updated on 24/May/20
letu=x−4=n+fwith0⩽f<12x+5=2(4+n+f)+5=2(4+n)+5+2fcase0⩽f<12:y=[2x+5]=2(4+n)+5+[2f]=13+2n=3n⇒n=13⇒x=4+n+f=17+fi.e.17⩽x<17.5[3x+y]=51+[3f]+39=90+[3f[=90or91case12⩽f<1:y=[2x+5]=2(4+n)+5+[2f]=14+2n=3n⇒n=14⇒x=4+n+f=18+fi.e.18.5⩽x<19[3x+y]=54+[3f]+42=96+[3f[=97or98⇒[3x+y]=90,91,97,98.
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