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Question Number 95309 by i jagooll last updated on 24/May/20

if y = [ 2x+5 ] = 3[x−4]   then [ 3x+y ] = ?

ify=[2x+5]=3[x4]then[3x+y]=?

Answered by mr W last updated on 24/May/20

let u=x−4=n+f with 0≤f<1  2x+5=2(4+n+f)+5=2(4+n)+5+2f  case 0≤f<(1/2):  y=[2x+5]=2(4+n)+5+[2f]=13+2n=3n  ⇒n=13  ⇒x=4+n+f=17+f  i.e. 17≤x<17.5  [3x+y]=51+[3f]+39=90+[3f[=90 or 91    case (1/2)≤f<1:  y=[2x+5]=2(4+n)+5+[2f]=14+2n=3n  ⇒n=14  ⇒x=4+n+f=18+f  i.e. 18.5≤x<19  [3x+y]=54+[3f]+42=96+[3f[=97 or 98    ⇒[3x+y]=90, 91, 97, 98.

letu=x4=n+fwith0f<12x+5=2(4+n+f)+5=2(4+n)+5+2fcase0f<12:y=[2x+5]=2(4+n)+5+[2f]=13+2n=3nn=13x=4+n+f=17+fi.e.17x<17.5[3x+y]=51+[3f]+39=90+[3f[=90or91case12f<1:y=[2x+5]=2(4+n)+5+[2f]=14+2n=3nn=14x=4+n+f=18+fi.e.18.5x<19[3x+y]=54+[3f]+42=96+[3f[=97or98[3x+y]=90,91,97,98.

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