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Question Number 95473 by aurpeyz last updated on 25/May/20

	Answered by EmericGent last updated on 25/May/20

	$r e g r o u p e v e r y t w o t e r m s$ $1 - \frac{1}{2} = \frac{1}{2}$ $a n d t h e n \forall n \in N *$ $\frac{1}{n} - \frac{1}{n + 1} = \frac{n + 1 - n}{n (n + 1)} = \frac{1}{n (n + 1)}$ $s i n c e n (n + 1) i s a n o n z e r o p o s i t i v e$ $i n t e g e r, \frac{1}{n (n + 1)} i s g r e a t e r t h a n 0$ $s o y o u r s u m i s j u s t a s u m o f p o s i t i v e$ $t e r m s, s o {i t}^{'} s a l s o p o s i t i v e$
	Commented by aurpeyz last updated on 06/Jun/20

	$P l e a s e e x p l a i n . i d o n o t s e e m t o u n d e r s t a n d . p l a$
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