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Question Number 95502 by bobhans last updated on 25/May/20

6 man + 8 woman ⇒working a job in 10 days  26 man + 48 woman ⇒ in 2 days  if 15 man + 20 woman ⇒ ?? days

$$\mathrm{6}\:\mathrm{man}\:+\:\mathrm{8}\:\mathrm{woman}\:\Rightarrow\mathrm{working}\:\mathrm{a}\:\mathrm{job}\:\mathrm{in}\:\mathrm{10}\:\mathrm{days} \\ $$$$\mathrm{26}\:\mathrm{man}\:+\:\mathrm{48}\:\mathrm{woman}\:\Rightarrow\:\mathrm{in}\:\mathrm{2}\:\mathrm{days} \\ $$$$\mathrm{if}\:\mathrm{15}\:\mathrm{man}\:+\:\mathrm{20}\:\mathrm{woman}\:\Rightarrow\:??\:\mathrm{days} \\ $$

Commented by bobhans last updated on 25/May/20

my answer 4 days. it correct?

$$\mathrm{my}\:\mathrm{answer}\:\mathrm{4}\:\mathrm{days}.\:\mathrm{it}\:\mathrm{correct}? \\ $$

Commented by john santu last updated on 25/May/20

yes. correct

$$\mathrm{yes}.\:\mathrm{correct}\: \\ $$

Commented by bobhans last updated on 25/May/20

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

Answered by john santu last updated on 25/May/20

(1)(6p+8q).10 = s  (2) (26p+48q).2 = s  (3)(15p+20q).x = s  ⇒10(6p+8q) = 2(26p+48q)  20(3p+4q) = 4(13p+24q)  15p+20q = 13p+24q  2p = 4q ⇒ p = 2q   ⇒(15.2q+20q).x = 2(26.2q+48q)  x = ((2×100)/(50)) = 4 days

$$\left(\mathrm{1}\right)\left(\mathrm{6p}+\mathrm{8q}\right).\mathrm{10}\:=\:\mathrm{s} \\ $$$$\left(\mathrm{2}\right)\:\left(\mathrm{26p}+\mathrm{48q}\right).\mathrm{2}\:=\:\mathrm{s} \\ $$$$\left(\mathrm{3}\right)\left(\mathrm{15p}+\mathrm{20q}\right).{x}\:=\:{s} \\ $$$$\Rightarrow\mathrm{10}\left(\mathrm{6p}+\mathrm{8q}\right)\:=\:\mathrm{2}\left(\mathrm{26p}+\mathrm{48q}\right) \\ $$$$\mathrm{20}\left(\mathrm{3p}+\mathrm{4q}\right)\:=\:\mathrm{4}\left(\mathrm{13p}+\mathrm{24q}\right) \\ $$$$\mathrm{15p}+\mathrm{20q}\:=\:\mathrm{13p}+\mathrm{24q} \\ $$$$\mathrm{2p}\:=\:\mathrm{4q}\:\Rightarrow\:\mathrm{p}\:=\:\mathrm{2q}\: \\ $$$$\Rightarrow\left(\mathrm{15}.\mathrm{2q}+\mathrm{20q}\right).{x}\:=\:\mathrm{2}\left(\mathrm{26}.\mathrm{2}{q}+\mathrm{48}{q}\right) \\ $$$${x}\:=\:\frac{\mathrm{2}×\mathrm{100}}{\mathrm{50}}\:=\:\mathrm{4}\:{days} \\ $$

Commented by i jagooll last updated on 25/May/20

yesss

$$\mathrm{yesss} \\ $$

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