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Question Number 95502 by bobhans last updated on 25/May/20

$$6\mathrm{man}+8\mathrm{woman}\Rightarrow \mathrm{working}\mathrm{a}\mathrm{job}\mathrm{in}10\mathrm{days}$$$$26\mathrm{man}+48\mathrm{woman}\Rightarrow \mathrm{in}2\mathrm{days}$$$$\mathrm{if}15\mathrm{man}+20\mathrm{woman}\Rightarrow ??\mathrm{days}$$

Commented by bobhans last updated on 25/May/20

$$\mathrm{my}\mathrm{answer}4\mathrm{days}.\mathrm{it}\mathrm{correct}?$$

Commented by john santu last updated on 25/May/20

$$\mathrm{yes}.\mathrm{correct}$$

Commented by bobhans last updated on 25/May/20

$$\mathrm{thank}\mathrm{you}$$

Answered by john santu last updated on 25/May/20

$$\left(1\right)(6\mathrm{p}+8\mathrm{q}).10=\mathrm{s}$$$$\left(2\right)(26\mathrm{p}+48\mathrm{q}).2=\mathrm{s}$$$$\left(3\right)(15\mathrm{p}+20\mathrm{q}).x=s$$$$\Rightarrow 10(6\mathrm{p}+8\mathrm{q})=2(26\mathrm{p}+48\mathrm{q})$$$$20(3\mathrm{p}+4\mathrm{q})=4(13\mathrm{p}+24\mathrm{q})$$$$15\mathrm{p}+20\mathrm{q}=13\mathrm{p}+24\mathrm{q}$$$$2\mathrm{p}=4\mathrm{q}\Rightarrow \mathrm{p}=2\mathrm{q}$$$$\Rightarrow (15.2\mathrm{q}+20\mathrm{q}).x=2(26.2q+48q)$$$$x=\frac{2\times 100}{50}=4days$$

Commented by i jagooll last updated on 25/May/20

$$\mathrm{yesss}$$

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