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Question Number 9553 by tawakalitu last updated on 14/Dec/16

Find :   u∙v  (i)   f(z) = ∣z∣^2   (ii)  f(z) = z + (1/z)

$$\mathrm{Find}\::\:\:\:\mathrm{u}\centerdot\mathrm{v} \\ $$$$\left(\mathrm{i}\right)\:\:\:\mathrm{f}\left(\mathrm{z}\right)\:=\:\mid\mathrm{z}\mid^{\mathrm{2}} \\ $$$$\left(\mathrm{ii}\right)\:\:\mathrm{f}\left(\mathrm{z}\right)\:=\:\mathrm{z}\:+\:\frac{\mathrm{1}}{\mathrm{z}} \\ $$

Commented by geovane10math last updated on 14/Dec/16

z is complex ?

$${z}\:\mathrm{is}\:\mathrm{complex}\:? \\ $$

Commented by tawakalitu last updated on 15/Dec/16

yes sir.

$$\mathrm{yes}\:\mathrm{sir}. \\ $$

Commented by geovane10math last updated on 15/Dec/16

This “u ∙ v” is  ∫u dv = uv − ∫v du  ?

$$\mathrm{This}\:``\mathrm{u}\:\centerdot\:\mathrm{v}''\:\mathrm{is} \\ $$$$\int{u}\:{dv}\:=\:\boldsymbol{{uv}}\:−\:\int{v}\:{du}\:\:? \\ $$

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