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Question Number 95531 by Abdulrahman last updated on 25/May/20

$$\frac{\mathrm{tanx}\times \mathrm{ctg}2\mathrm{x}}{{\tan }^2\mathrm{x}-1}=?$$

Commented by PRITHWISH SEN 2 last updated on 25/May/20

$$\mathrm{put}\cot 2\mathrm{x}=\frac{1-\tan {}^2\mathrm{x}}{2\tan \mathrm{x}}$$

Commented by Abdulrahman last updated on 25/May/20

$$\mathrm{then}?$$$$\mathrm{please}\mathrm{solve}\mathrm{it}$$

Commented by Tony Lin last updated on 25/May/20

$$\frac{tanxcot2x}{{tan}^{2}x-1}$$$$=\frac{tanx\frac{1-{tan}^{2}x}{2tanx}}{{tan}^{2}x-1}$$$$=-\frac{1}{2}$$

Commented by PRITHWISH SEN 2 last updated on 25/May/20

$$\mathrm{Are}\mathrm{you}\mathrm{a}\mathrm{boy}\mathrm{or}\mathrm{an}\mathrm{adult}?$$

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