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Question Number 95563 by peter frank last updated on 26/May/20

$$\int \frac{{\mathrm{ax}}^2+\mathrm{bx}+\mathrm{c}}{(\mathrm{x}-\mathrm{p})(\mathrm{x}-\mathrm{q})(\mathrm{x}-\mathrm{r})}\mathrm{dx}$$

Answered by MJS last updated on 26/May/20

$$\int \frac{{ax}^2+bx+c}{(x-p)(x-q)(x-r)}dx=$$$$=\frac{{ap}^2+bp+c}{(p-q)(p-r)}\int \frac{dx}{x-p}+$$$$+\frac{{aq}^2+bq+c}{(q-p)(q-r)}\int \frac{dx}{x-q}+$$$$+\frac{{ar}^2+br+c}{(r-p)(r-q)}\int \frac{dx}{x-r}$$$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{easy}\mathrm{now}$$

Commented by 1549442205 last updated on 26/May/20

$$\mathrm{Allright},\mathrm{it}\mathrm{is}\mathrm{correct}$$

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