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Question Number 95563 by peter frank last updated on 26/May/20

∫((ax^2 +bx+c)/((x−p)(x−q)(x−r)))dx

$$\int\frac{\mathrm{ax}^{\mathrm{2}} +\mathrm{bx}+\mathrm{c}}{\left(\mathrm{x}−\mathrm{p}\right)\left(\mathrm{x}−\mathrm{q}\right)\left(\mathrm{x}−\mathrm{r}\right)}\mathrm{dx} \\ $$

Answered by MJS last updated on 26/May/20

∫((ax^2 +bx+c)/((x−p)(x−q)(x−r)))dx=  =((ap^2 +bp+c)/((p−q)(p−r)))∫(dx/(x−p))+  +((aq^2 +bq+c)/((q−p)(q−r)))∫(dx/(x−q))+  +((ar^2 +br+c)/((r−p)(r−q)))∫(dx/(x−r))  it′s easy now

$$\int\frac{{ax}^{\mathrm{2}} +{bx}+{c}}{\left({x}−{p}\right)\left({x}−{q}\right)\left({x}−{r}\right)}{dx}= \\ $$$$=\frac{{ap}^{\mathrm{2}} +{bp}+{c}}{\left({p}−{q}\right)\left({p}−{r}\right)}\int\frac{{dx}}{{x}−{p}}+ \\ $$$$+\frac{{aq}^{\mathrm{2}} +{bq}+{c}}{\left({q}−{p}\right)\left({q}−{r}\right)}\int\frac{{dx}}{{x}−{q}}+ \\ $$$$+\frac{{ar}^{\mathrm{2}} +{br}+{c}}{\left({r}−{p}\right)\left({r}−{q}\right)}\int\frac{{dx}}{{x}−{r}} \\ $$$$\mathrm{it}'\mathrm{s}\:\mathrm{easy}\:\mathrm{now} \\ $$

Commented by 1549442205 last updated on 26/May/20

Allright,it is correct

$$\mathrm{Allright},\mathrm{it}\:\mathrm{is}\:\mathrm{correct} \\ $$

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