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Question Number 95699 by i jagooll last updated on 27/May/20

$$\mathrm{many}\mathrm{digits}\mathrm{of}\mathrm{number}$$$$5^8\times 4^5\times 7$$

Commented by Rasheed.Sindhi last updated on 27/May/20

$$5^8\times 4^5\times 7=5^8\times {\left(2^2\right)}^5\times 7$$$$5^8\times 2^8\times 2^2\times 7$$$$7\times 4\times {\left(5\times 2\right)}^8$$$$28\times {10}^8$$$$10digits$$

Commented by PRITHWISH SEN 2 last updated on 27/May/20

$$\mathrm{wow}!$$

Commented by i jagooll last updated on 27/May/20

$$\mathrm{cooll}$$

Commented by Rasheed.Sindhi last updated on 27/May/20

$$\mathcal{T}h\mathrm{\forall }nkyoubothsirs!$$

Answered by i jagooll last updated on 27/May/20

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