use cylinder ring method y = 2x−1 y = −2x + 3 x = 2 y−axis


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Question Number 95722 by rb222 last updated on 27/May/20

$u s e c y l i n d e r r i n g m e t h o d$ $y = 2 x - 1$ $y = - 2 x + 3$ $x = 2$ $y - a x i s$
	Answered by i jagooll last updated on 27/May/20

	$vol = 2 π {\int^{2}}_{1} x (2 x - 1 - (- 2 x + 3)) d x$ $= 2 π {\int^{2}}_{1} x (4 x - 4) d x$ $= 2 π {\int^{2}}_{1} (4 x^{2} - 4 x) d x$ $= 2 π {[\frac{4}{3} x^{3} - 2 x^{2}]}_{1}^{2}$ $= 2 π [\frac{4}{3} (7) - 2 (3)]$ $= 2 π (\frac{28 - 18}{3}) = \frac{20 π}{3}$
	Commented by rb222 last updated on 27/May/20

	$t h a n k s s i r$
	Answered by john santu last updated on 27/May/20

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