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Question Number 95779 by i jagooll last updated on 27/May/20

if plane 3x+4y+tz=2 and   kx+6y+5z−2=0 are parallel.  find the value of k and t

ifplane3x+4y+tz=2andkx+6y+5z2=0areparallel.findthevalueofkandt

Answered by john santu last updated on 27/May/20

(3/k) = (4/6) = (t/5)   { ((k=((18)/4)=(9/2) )),((t = ((20)/6)=((10)/3))) :}

3k=46=t5{k=184=92t=206=103

Commented by i jagooll last updated on 27/May/20

thank you

thankyou

Answered by Rio Michael last updated on 28/May/20

normal for plane 1 n_1  = 3i + 4j + tk  normal for plane 2 n_2 = ki + 6j + 5k  for parrallel vectors a^→  and b^→  , a^→ = h b^→  where h is a constant h ∈R  ⇒ (3i + 4j + tk) = h(ki + 6j + 5k)    ⇒  4 = 6h ⇔ h = (2/3)  also 3 = hk ⇒  k = (3/h) = 3 × (3/2)  , k = (9/2)  and t = 5h ⇒  t = ((10)/3)

normalforplane1n1=3i+4j+tknormalforplane2n2=ki+6j+5kforparrallelvectorsaandb,a=hbwherehisaconstanthR(3i+4j+tk)=h(ki+6j+5k)4=6hh=23also3=hkk=3h=3×32,k=92andt=5ht=103

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