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Question Number 95779 by i jagooll last updated on 27/May/20
ifplane3x+4y+tz=2andkx+6y+5z−2=0areparallel.findthevalueofkandt
Answered by john santu last updated on 27/May/20
3k=46=t5{k=184=92t=206=103
Commented by i jagooll last updated on 27/May/20
thankyou
Answered by Rio Michael last updated on 28/May/20
normalforplane1n1=3i+4j+tknormalforplane2n2=ki+6j+5kforparrallelvectorsa→andb→,a→=hb→wherehisaconstanth∈R⇒(3i+4j+tk)=h(ki+6j+5k)⇒4=6h⇔h=23also3=hk⇒k=3h=3×32,k=92andt=5h⇒t=103
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