((9x^2 +4a^2 )/(9x^2 −4a^2 )) +((3x)/(3x+2a)) −((2a)/(2a−3x))


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Question Number 96007 by 6532 last updated on 29/May/20

$\frac{{9 x}^{2} + {4 a}^{2}}{{9 x}^{2} - {4 a}^{2}} + \frac{3 x}{3 x + 2 a} - \frac{2 a}{2 a - 3 x}$
Commented by i jagooll last updated on 29/May/20

$\frac{9 x^{2} + 4 a^{2}}{9 x^{2} - 4 a^{2}} + \frac{3 x}{3 x + 2 a} + \frac{2 a}{3 x - 2 a} =$ $\frac{9 x^{2} + 4 a^{2} + 9 x^{2} - 6 a x + 6 a x + 4 a^{2}}{9 x^{2} - 4 a^{2}} =$ $\frac{18 x^{2} + 8 a^{2}}{9 x^{2} - 4 a^{2}}$
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