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Question Number 96008 by 6532 last updated on 29/May/20

$$\frac{1-\frac{1}{\mathrm{a}}}{{\mathrm{a}}^2-\frac{1}{{\mathrm{a}}^2}}$$

Commented by john santu last updated on 29/May/20

$$\frac{a^2-a}{a^4-1}=\frac{a(a-1)}{(a-1)(a+1)(a^2+1)}$$$$=\frac{a}{(a+1)(a^2+1)}$$

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