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Question Number 96076 by bobhans last updated on 29/May/20
∫3x.2xdx?
Answered by i jagooll last updated on 29/May/20
∫(3x)d(2xln2)=3x.2xln2−3∫2xln2dx=3x.2xln2−3.2x(ln2)2+c
Answered by abdomathmax last updated on 29/May/20
I=∫3x2xdx⇒I=3∫xexln2dxbypartsu=xandv′=ecln2⇒I=3{xln2exln2−∫1ln2exln2dx}=3xln2×2x−3.2x(ln2)2+C
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