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Question Number 96197 by mathmax by abdo last updated on 30/May/20

$$\mathrm{calculate}{\int }_0^{\mathrm{\infty }}\frac{\mathrm{ch}(\mathrm{cosx}-\mathrm{sinx})}{{\mathrm{x}}^2+4}\mathrm{dx}$$

Answered by mathmax by abdo last updated on 01/Jun/20

$$\mathrm{the}\mathrm{Q}\mathrm{is}\mathrm{calculate}{\int }_{-\mathrm{\infty }}^{+\mathrm{\infty }}\frac{\mathrm{ch}(\mathrm{cosx}-\mathrm{sinx})}{{\mathrm{x}}^2+4}\mathrm{dx}$$

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