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Question Number 96290 by 175 last updated on 31/May/20
If:tan(x+iy)=a+bithenfinda,b
Commented by Tony Lin last updated on 31/May/20
tan(x+iy)=tanx+taniy1−tanxtaniy=tanx+itanhy1−tanx⋅itanhy=(tanx−tanhyi)(1+tanxtanhyi)(1−tanxtanhyi)(1+tanxtanhyi)=tanx+tanxtanh2y1+tan2xtanh2y+tan2xtanhy−tanhy1+tan2xtanh2yi
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