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Question Number 96397 by mathocean1 last updated on 01/Jun/20

Hello  If  5000F is the price to carry 5 tonnes  of water on 5 kilometers, what is the  price to carry 60 tonnes on 70.5   kilometers?  please explain if possible...

$${Hello} \\ $$$${If}\:\:\mathrm{5000}{F}\:{is}\:{the}\:{price}\:{to}\:{carry}\:\mathrm{5}\:{tonnes} \\ $$$${of}\:{water}\:{on}\:\mathrm{5}\:{kilometers},\:{what}\:{is}\:{the} \\ $$$${price}\:{to}\:{carry}\:\mathrm{60}\:{tonnes}\:{on}\:\mathrm{70}.\mathrm{5}\: \\ $$$${kilometers}? \\ $$$${please}\:{explain}\:{if}\:{possible}... \\ $$

Answered by 1549442205 last updated on 01/Jun/20

price to carry 1 tone on 1 kilometer is  5000:(5×5)=200F.Hence,price to carry  60 tonnes of water on 70.5 lilometers  equal to 200×60×70.5=846000 F

$$\mathrm{price}\:\mathrm{to}\:\mathrm{carry}\:\mathrm{1}\:\mathrm{tone}\:\mathrm{on}\:\mathrm{1}\:\mathrm{kilometer}\:\mathrm{is} \\ $$$$\mathrm{5000}:\left(\mathrm{5}×\mathrm{5}\right)=\mathrm{200F}.\mathrm{Hence},\mathrm{price}\:\mathrm{to}\:\mathrm{carry} \\ $$$$\mathrm{60}\:\mathrm{tonnes}\:\mathrm{of}\:\mathrm{water}\:\mathrm{on}\:\mathrm{70}.\mathrm{5}\:\mathrm{lilometers} \\ $$$$\mathrm{equal}\:\mathrm{to}\:\mathrm{200}×\mathrm{60}×\mathrm{70}.\mathrm{5}=\mathrm{846000}\:\mathrm{F} \\ $$

Commented by mathocean1 last updated on 01/Jun/20

thank you sir!  Please if  we admit that the price  to carry 5 tonnes on 3 kilometers is  700F ... what is the price to carry 60  tonnes on 70.5 Km?  My answer  The price to carry one tonne on 1 Km  is 700:(5×3)≅46,67.  so the price is 46.67×60×70.5=197400.  Is it correct?

$${thank}\:{you}\:{sir}! \\ $$$${Please}\:{if}\:\:{we}\:{admit}\:{that}\:{the}\:{price} \\ $$$${to}\:{carry}\:\mathrm{5}\:{tonnes}\:{on}\:\mathrm{3}\:{kilometers}\:{is} \\ $$$$\mathrm{700}{F}\:...\:{what}\:{is}\:{the}\:{price}\:{to}\:{carry}\:\mathrm{60} \\ $$$${tonnes}\:{on}\:\mathrm{70}.\mathrm{5}\:{Km}? \\ $$$$\boldsymbol{{M}}{y}\:{a}\boldsymbol{{nswer}} \\ $$$$\boldsymbol{{T}}{he}\:{price}\:{to}\:{carry}\:{one}\:{tonne}\:{on}\:\mathrm{1}\:{Km} \\ $$$${is}\:\mathrm{700}:\left(\mathrm{5}×\mathrm{3}\right)\cong\mathrm{46},\mathrm{67}. \\ $$$${so}\:{the}\:{price}\:{is}\:\mathrm{46}.\mathrm{67}×\mathrm{60}×\mathrm{70}.\mathrm{5}=\mathrm{197400}. \\ $$$${Is}\:{it}\:{correct}? \\ $$

Commented by 1549442205 last updated on 01/Jun/20

Of course,It is correct!

$$\mathrm{Of}\:\mathrm{course},\mathrm{It}\:\mathrm{is}\:\mathrm{correct}! \\ $$

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