Question Number 96410 by joki last updated on 01/Jun/20
Commented by bemath last updated on 01/Jun/20
$$\mathrm{B} \\ $$$$\mathrm{2000}\left(\mathrm{1}+\mathrm{0}.\mathrm{06t}\right) \\ $$
Commented by joki last updated on 01/Jun/20
$${how}\:{solution}.{step}\:\:{by}\:{step}? \\ $$
Commented by prakash jain last updated on 01/Jun/20
$$\mathrm{For}\:\mathrm{simple}\:\mathrm{interest}\:\mathrm{amount}\: \\ $$$$\mathrm{each}\:\mathrm{year}=\mathrm{2000}×\frac{\mathrm{6}}{\mathrm{100}} \\ $$$$\mathrm{interest}\:\mathrm{in}\:{t}\:\mathrm{years}=\mathrm{2000}×.\mathrm{06}{t} \\ $$$$\mathrm{total}\:\mathrm{value}=\mathrm{2000}+\mathrm{2000}×.\mathrm{06t} \\ $$$$=\mathrm{2000}\left(\mathrm{1}+.\mathrm{06}{t}\right) \\ $$
Commented by joki last updated on 01/Jun/20
$${thnks}\:{sir} \\ $$