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Question Number 96497 by Fikret last updated on 02/Jun/20

Answered by Farruxjano last updated on 02/Jun/20

Commented by prakash jain last updated on 02/Jun/20

$$\mathrm{I}\mathrm{think}\mathrm{instead}\mathrm{of}2013!$$$$\mathrm{you}\mathrm{should}\mathrm{get}=\frac{2^{1008}\times 1008!}{n!}$$$$n=1008?$$

Commented by Farruxjano last updated on 02/Jun/20

$$\mathrm{Oh},\mathrm{yes}{\mathrm{you}}^{\prime }\mathrm{re}\mathrm{right}!\mathrm{Sorrt}\mathrm{for}\mathrm{the}\mathrm{simple}\mathrm{mistake}$$

Answered by Farruxjano last updated on 02/Jun/20

$$\mathrm{I}\mathrm{solved}\mathrm{as}\mathrm{I}\mathrm{could}\mathrm{but}\mathrm{i}{\mathrm{couldn}}^{\prime }\mathrm{t}\mathrm{find}\mathrm{the}\mathrm{answer}:($$

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