Question Number 96548 by Hamida last updated on 02/Jun/20
Commented by bobhans last updated on 02/Jun/20
$$\mathrm{y}'=−\mathrm{6e}^{−\mathrm{6x}} \:+\:\mathrm{8}\:\mathrm{cos}\:\mathrm{8x}\:\ldots\ldots\ldots \\ $$
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Question Number 96548 by Hamida last updated on 02/Jun/20 | ||
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Commented by bobhans last updated on 02/Jun/20 | ||
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$$\mathrm{y}'=−\mathrm{6e}^{−\mathrm{6x}} \:+\:\mathrm{8}\:\mathrm{cos}\:\mathrm{8x}\:\ldots\ldots\ldots \\ $$ | ||