Question Number 966 by rpatle69@gmail.com last updated on 09/May/15 | ||
$$\int{e}^{−{x}} \:{dx}=?\:{please}\:{answer}\:{me}\:{soon}\:{guys} \\ $$$$ \\ $$$$ \\ $$ | ||
Answered by prakash jain last updated on 09/May/15 | ||
$$−{x}={u}\Rightarrow−{dx}={du} \\ $$$$\int\:{e}^{−{x}} {dx}=−\int{e}^{{u}} {du}=−{e}^{{u}} +{C}=−{e}^{−{x}} +{C} \\ $$ | ||
Commented by rpatle69@gmail.com last updated on 09/May/15 | ||
$${thanks} \\ $$ | ||