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Question Number 96600 by Hamida last updated on 03/Jun/20

Answered by Rio Michael last updated on 03/Jun/20

$$y=\frac{4}{7}{x}^3-\frac{2}{3}{x}^{-1}$$$$y{}^{\prime }=\frac{12}{7}{x}^3+\frac{2}{3x^2}$$$$y^{\prime }{\mid }_{x=7}=12{\left(7\right)}^2+\frac{2}{3\left(7^2\right)}$$

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