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Question Number 96685 by Ar Brandon last updated on 03/Jun/20

$$\underset{\omega \to \mathrm{\infty }}{\lim 20log}\sqrt{1+{\left(\frac{\omega }{100}\right)}^2}$$

Answered by Rio Michael last updated on 04/Jun/20

$$\mathrm{By}{\mathrm{l}}^{\prime }\mathrm{hopitals}\mathrm{rule}\mathrm{i}\mathrm{get}+\mathrm{\infty }\mathrm{as}\mathrm{answer}$$

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