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Question Number 96784 by 175 last updated on 04/Jun/20
Answered by Sourav mridha last updated on 04/Jun/20
=∫2+x2+xx2x2+x+1dx+2x=∫d(x+12)(x+12)2+(32)2+2x−2∫d[x2+x+1x]+c=ln[(x+12)+x2+x+1]−2.x2+x+1x+2x+c
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