Question Number 96866 by bobhans last updated on 05/Jun/20
Commented by john santu last updated on 05/Jun/20
$$\mathrm{ratio}\:=\:\frac{\mathrm{4}\sqrt{\mathrm{5}}×\mathrm{4}\sqrt{\mathrm{5}}}{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} +\left(\mathrm{8}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} } \\ $$$$=\:\frac{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} \left(\mathrm{1}+\mathrm{2}^{\mathrm{2}} \right)}\:=\:\mathrm{1}:\:\mathrm{5} \\ $$
Answered by Sourav mridha last updated on 05/Jun/20
$$\boldsymbol{{ratio}}:\frac{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} +\left(\mathrm{8}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{5}} \\ $$
Commented by bemath last updated on 05/Jun/20
$$\mathrm{the}\:\mathrm{first}\:\mathrm{your}\:\mathrm{answer}\:\mathrm{is}\: \\ $$$$\frac{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }{\sqrt{\left(\mathrm{4}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} +\left(\mathrm{8}\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }} \\ $$
Commented by john santu last updated on 05/Jun/20
$$\mathrm{no} \\ $$
Commented by bemath last updated on 05/Jun/20
$$\mathrm{your}\:\mathrm{changed}\:\mathrm{answer} \\ $$
Commented by Sourav mridha last updated on 05/Jun/20
what no!!!!
Commented by Sourav mridha last updated on 05/Jun/20
yeah at first I put √,but when I rechaked it then edited my ans...but then there was no comment...yeah it's okk..just typing error and I often do so..
Commented by bobhans last updated on 05/Jun/20
$$\mathrm{yes}\:.\:\mathrm{thank}\:\mathrm{you} \\ $$