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Question Number 96922 by M±th+et+s last updated on 05/Jun/20

Commented by M±th+et+s last updated on 05/Jun/20

$p r o v e t h a t : r_{1} + r_{3} + r_{5} = r_{2} + r_{4} +_{6}$
Commented by mr W last updated on 05/Jun/20

$s y m m e t r y :$ $r_{1} = r_{6}$ $r_{2} = r_{5}$ $r_{3} = r_{4}$ $\Rightarrow r_{1} + r_{3} + r_{5} = r_{2} + r_{4} + r_{6}$
Commented by M±th+et+s last updated on 05/Jun/20

$b u t t h e a d j a c e n t 2 t r i a n g l e s a r o u n d t h e$ $r i g h t a n g l e a r e n o t n e c e s s a r i l y c o n g r u n e t$
Commented by mr W last updated on 05/Jun/20

$g i v e a n e x a m p l e p l e a s e .$
Commented by M±th+et+s last updated on 05/Jun/20

$y e s s i r$ $i m e a n y o u c a n n o t a s s u m e r_{1} = r_{6}$ $b e c a u s e t h e c i r c l e l o o k l i k e s a m e$
Commented by M±th+et+s last updated on 05/Jun/20

$i t s h o u l d b e p r o v e d g e o m e t r y$
Commented by mr W last updated on 05/Jun/20

$i d i d i t w i t h t h e w o r d ‘ ‘ {s y m m e t r y}^{″} .$ ${i t}^{'} s t o o e a s y t o p r o v e a n d a l s o o b v i o u s .$
Commented by mr W last updated on 05/Jun/20

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