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Question Number 96947 by RAMANA last updated on 05/Jun/20

Commented by PRITHWISH SEN 2 last updated on 05/Jun/20

$$\mathrm{Total}\mathrm{sample}\mathrm{space}\mathrm{s}\left(\mathrm{n}\right)={\mathrm{C}}_3^{100}$$$$\mathrm{Number}\mathrm{of}\mathrm{favourable}\mathrm{cases}$$$$\mathbf{common}\mathbf{ratio}{1}^{\mathbf{st}}\mathbf{term}\mathbf{ranges}\mathbf{No}.\mathbf{of}\mathbf{cases}$$$$\mathbf{from}\mathbf{to}$$$$21\mathrm{to}2525$$$$31\mathrm{to}1111$$$$41\mathrm{to}66$$$$51\mathrm{to}44$$$$61\mathrm{to}22$$$$71\mathrm{to}22$$$$81\mathrm{to}11$$$$91\mathrm{to}11$$$$101\mathrm{to}11$$$$\therefore \mathbf{n}\left(\mathbf{A}\right)=53$$$$\therefore \mathbf{The}\mathbf{required}\mathbf{probability}$$$$\mathbf{P}\left(\mathbf{A}\right)=\frac{53}{{\mathbf{C}}_3^{100}}=\frac{53\times 6}{100\times 99\times 98}=\frac{53}{161700}$$

Commented by RAMANA last updated on 05/Jun/20

$$\mathrm{welldone}..\mathrm{Thanks}\mathrm{sir}..$$

Commented by 1549442205 last updated on 06/Jun/20

$$\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{understand}{}^{″}{\mathrm{GP}}^{″}\mathrm{what}\mathrm{do}\mathrm{you}\mathrm{mean}?$$$$\mathrm{can}\mathrm{you}\mathrm{explain}\mathrm{clearly}?$$

Commented by RAMANA last updated on 07/Jun/20

$$\mathrm{It}\mathrm{is}\mathrm{Geometric}\mathrm{progression}$$

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