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Question Number 96979 by  M±th+et+s last updated on 05/Jun/20

∫_0 ^π arctan(3^(cos(x)) )dx

0πarctan(3cos(x))dx

Answered by MJS last updated on 06/Jun/20

y=arctan 3^(cos x) ; x∈[0; π]  this is point symmetric, the center is  C= (((π/2)),((π/4)) )  ⇒  the value of the integral is (π^2 /4)

y=arctan3cosx;x[0;π]thisispointsymmetric,thecenterisC=(π2π4)thevalueoftheintegralisπ24

Commented by  M±th+et+s last updated on 06/Jun/20

well done sir

welldonesir

Commented by  M±th+et+s last updated on 06/Jun/20

sir mjs can you explain the rule and  when can i use it and thank you

sirmjscanyouexplaintheruleandwhencaniuseitandthankyou

Commented by MJS last updated on 06/Jun/20

we have to find out if there′s some kind of  symmetry within the interval... I′m not  sure if there′s a rule  here  arctan (1/α) =−arctan α  α=3^(cos x) ; −1≤cos x ≤1 ⇒ (1/3)≤α≤3  ⇒ center is at cos x =0  the rest is easy

wehavetofindoutiftheressomekindofsymmetrywithintheinterval...Imnotsureiftheresaruleherearctan1α=arctanαα=3cosx;1cosx113α3centerisatcosx=0therestiseasy

Commented by  M±th+et+s last updated on 06/Jun/20

thanx

thanx

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