Question and Answers Forum

All Questions      Topic List

UNKNOWN Questions

Previous in All Question      Next in All Question      

Previous in UNKNOWN      Next in UNKNOWN      

Question Number 9707 by Fahad last updated on 27/Dec/16

How many paving stones each measuring  2.5m×2m are required to pave a rectangular  courtyard 30m long and 16.5 m wide?

$$\mathrm{How}\:\mathrm{many}\:\mathrm{paving}\:\mathrm{stones}\:\mathrm{each}\:\mathrm{measuring} \\ $$$$\mathrm{2}.\mathrm{5m}×\mathrm{2m}\:\mathrm{are}\:\mathrm{required}\:\mathrm{to}\:\mathrm{pave}\:\mathrm{a}\:\mathrm{rectangular} \\ $$$$\mathrm{courtyard}\:\mathrm{30m}\:\mathrm{long}\:\mathrm{and}\:\mathrm{16}.\mathrm{5}\:\mathrm{m}\:\mathrm{wide}? \\ $$

Commented by ridwan balatif last updated on 27/Dec/16

area of courtyard=30×16.5=495 m^2   area of stone=2.5×2=5 m  n=((area of courtyard)/(area of stone))  n=((495)/5)  n=99 stones

$$\mathrm{area}\:\mathrm{of}\:\mathrm{courtyard}=\mathrm{30}×\mathrm{16}.\mathrm{5}=\mathrm{495}\:\mathrm{m}^{\mathrm{2}} \\ $$$$\mathrm{area}\:\mathrm{of}\:\mathrm{stone}=\mathrm{2}.\mathrm{5}×\mathrm{2}=\mathrm{5}\:\mathrm{m} \\ $$$$\mathrm{n}=\frac{\mathrm{area}\:\mathrm{of}\:\mathrm{courtyard}}{\mathrm{area}\:\mathrm{of}\:\mathrm{stone}} \\ $$$$\mathrm{n}=\frac{\mathrm{495}}{\mathrm{5}} \\ $$$$\mathrm{n}=\mathrm{99}\:\mathrm{stones} \\ $$

Answered by sandy_suhendra last updated on 28/Dec/16

((30)/2)×((16.5)/(2.5))≈15×7=105

$$\frac{\mathrm{30}}{\mathrm{2}}×\frac{\mathrm{16}.\mathrm{5}}{\mathrm{2}.\mathrm{5}}\approx\mathrm{15}×\mathrm{7}=\mathrm{105} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com