Question Number 97089 by Mathudent last updated on 06/Jun/20 | ||
$${solve}\:\:\int{x}^{{x}} \left(\mathrm{1}+\mathrm{ln}\:{x}\right){dx}\:. \\ $$ | ||
Answered by M±th+et+s last updated on 06/Jun/20 | ||
$${let}\:{x}^{{x}} ={u}\:\:\:\:{du}={x}^{{x}} \left(\mathrm{1}+{ln}\left({x}\right)\right){dx} \\ $$$$\int{du}={u}+{c} \\ $$$$\int{x}^{{x}} \left(\mathrm{1}+{ln}\left({x}\right)\right){dx}={x}^{{x}} +{c} \\ $$ | ||
Commented by Mathudent last updated on 06/Jun/20 | ||
thank you | ||
Commented by M±th+et+s last updated on 06/Jun/20 | ||
$${you}\:{are}\:{welcome} \\ $$ | ||