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Question Number 97319 by bemath last updated on 07/Jun/20

If 5,6,11,17,28,45,73,x,y,z  then the value of x,y,z?__  (a) 118,192,309  (b) 117,191,310  (c) 117,191,308  (d) 118,192,310  (e) 118,191,309

$$\mathrm{If}\:\mathrm{5},\mathrm{6},\mathrm{11},\mathrm{17},\mathrm{28},\mathrm{45},\mathrm{73},\mathrm{x},\mathrm{y},\mathrm{z} \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x},\mathrm{y},\mathrm{z}?\_\_ \\ $$$$\left(\mathrm{a}\right)\:\mathrm{118},\mathrm{192},\mathrm{309} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{117},\mathrm{191},\mathrm{310} \\ $$$$\left(\mathrm{c}\right)\:\mathrm{117},\mathrm{191},\mathrm{308} \\ $$$$\left(\mathrm{d}\right)\:\mathrm{118},\mathrm{192},\mathrm{310} \\ $$$$\left(\mathrm{e}\right)\:\mathrm{118},\mathrm{191},\mathrm{309} \\ $$

Answered by bobhans last updated on 07/Jun/20

Fibonacci series  x = 45+73 = 118  y = 73+x = 73+118 = 191  z = x+y = 118 + 191 = 309 . (ans e )

$$\mathrm{Fibonacci}\:\mathrm{series} \\ $$$$\boldsymbol{{x}}\:=\:\mathrm{45}+\mathrm{73}\:=\:\mathrm{118} \\ $$$$\boldsymbol{{y}}\:=\:\mathrm{73}+\boldsymbol{{x}}\:=\:\mathrm{73}+\mathrm{118}\:=\:\mathrm{191} \\ $$$$\boldsymbol{{z}}\:=\:\boldsymbol{{x}}+\boldsymbol{{y}}\:=\:\mathrm{118}\:+\:\mathrm{191}\:=\:\mathrm{309}\:.\:\left(\boldsymbol{\mathrm{ans}}\:\boldsymbol{\mathrm{e}}\:\right) \\ $$

Commented by bemath last updated on 07/Jun/20

yes....

$$\mathrm{yes}.... \\ $$

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