Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 97526 by student work last updated on 08/Jun/20

$$\int \frac{\mathrm{dx}}{1+\sin \mathrm{x}}=?$$

Commented by bobhans last updated on 08/Jun/20

$$\frac{1}{1+\sin \mathrm{x}}\times \frac{1-\sin \mathrm{x}}{1-\sin \mathrm{x}}=\frac{1-\sin \mathrm{x}}{\cos {}^2\mathrm{x}}$$$$\int \sec {}^2\mathrm{x}-\sec \mathrm{x}\tan \mathrm{x}\mathrm{dx}=\tan \mathrm{x}-\sec \mathrm{x}+\mathrm{c}$$

Answered by smridha last updated on 08/Jun/20

$$\int \frac{{\mathit{s}\mathit{e}\mathit{c}}^2\frac{\mathit{x}}{2}\mathit{d}\mathit{x}}{1+{\mathit{t}\mathit{a}\mathit{n}}^2\frac{\mathit{x}}{2}+2\mathit{t}\mathit{a}\mathit{n}\frac{\mathit{x}}{2}}\mathit{d}\mathit{x}$$$$=2\int \frac{\mathit{d}(1+\mathit{t}\mathit{a}\mathit{n}\frac{\mathit{x}}{2})}{{(1+\mathit{t}\mathit{a}\mathit{n}\frac{\mathit{x}}{2})}^2}=-2\frac{1}{(1+\mathit{t}\mathit{a}\mathit{n}\frac{\mathit{x}}{2})}+\mathit{c}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com