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Question Number 97629 by peter frank last updated on 08/Jun/20

Answered by Rio Michael last updated on 09/Jun/20

$$\mathrm{mass}\mathrm{of}\mathrm{man}=100\mathrm{kg}$$$$\mathrm{height}\mathrm{jumped}=5\mathrm{m}$$$$\mathrm{time}=0.4\mathrm{s}$$$$\mathrm{Velocity}\mathrm{of}\mathrm{the}\mathrm{dude}v=\sqrt{2gh}=\sqrt{2\times 9.8{\mathrm{ms}}^{-2}\times 5\mathrm{m}}=9.9{\mathrm{ms}}^{-1}$$$$\mathrm{Force}\mathrm{F}=\frac{m\mathrm{\Delta }v}{t}=\frac{m(v_2-v_1)}{t}=\frac{100\mathrm{kg}(0-9.9){\mathrm{ms}}^{-1}}{0.4\mathrm{s}}\approx -2500\mathrm{N}$$$$\mathbf{the}\mathbf{negative}\mathbf{indicates}\mathbf{that}\mathbf{the}\mathbf{direction}\mathbf{of}\mathbf{the}\mathbf{force}\mathbf{opposes}\mathbf{motion}.$$$$\mathrm{weight}\mathrm{of}\mathrm{dude}=\mathrm{mgh}=100\mathrm{kg}\times 9.8{\mathrm{ms}}^{-2}=980\mathrm{N}$$$$\Rightarrow \mathrm{Average}\mathrm{force}=\mathrm{W}+\mathrm{F}=2500\mathrm{N}+980\mathrm{N}=......$$$$$$

Commented by Rio Michael last updated on 09/Jun/20

$$\mathrm{thanks}\mathrm{Mr}\mathrm{W}\mathrm{for}\mathrm{spoting}\mathrm{that}$$

Commented by mr W last updated on 09/Jun/20

$$wrong.$$$$mghisneveraforce!$$

Commented by Rio Michael last updated on 09/Jun/20

$$\mathrm{hahh}\mathrm{sorry}\mathrm{that}\mathrm{should}\mathrm{be}\mathrm{an}\mathrm{error},\mathrm{due}\mathrm{excitement}$$$$\mathrm{of}\mathrm{the}\mathrm{question}.$$$$\mathrm{Bro},\mathrm{Weight}\mathrm{of}\mathrm{the}\mathrm{dude}=\mathrm{mg}=100\mathrm{kg}\times 9.8{\mathrm{ms}}^{-2}=980\mathrm{N}$$

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