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Question Number 97759 by bobhans last updated on 09/Jun/20
∫sin5(x)dxcos(x)?
Answered by bemath last updated on 09/Jun/20
∫(1−cos2x)2sinxdxcosx=setcosx=z⇒−sinxdx=2zdz∫(1−z4)2z(−2zdz)=−2∫(1−2z4+z8)dz=−2z+45z5−29z9+c=−2cosx+45cos2xcosx−29cos4xcosx+c
Commented by bobhans last updated on 09/Jun/20
alright
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