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Question Number 97784 by 175 last updated on 09/Jun/20

$$Iff\left(x\right)={\left({\left({\left(x\right)}^{\frac{1}{2}}\right)}^{\frac{1}{2}}\right)}^{\text{iddots}}$$$$find:\frac{dy}{dx}$$

Answered by mr W last updated on 09/Jun/20

$$f\left(x\right)=\underset{n\to \mathrm{\infty }}{\lim }{x}^{{\left(\frac{1}{2}\right)}^n}=x^0=1$$$$\frac{dy}{dx}=0$$

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