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Question Number 97840 by bemath last updated on 10/Jun/20

$$\underset{\gamma \to 0}{\lim }(\mathrm{arc}\sin \frac{\mathrm{k}\cos \gamma }{\sqrt{1+{\mathrm{k}}^2}}-\mathrm{arc}\sin \frac{\mathrm{k}}{\sqrt{1+{\mathrm{k}}^2}})=?$$

Commented by john santu last updated on 10/Jun/20

$$=0$$

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