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Question Number 97920 by Lekhraj last updated on 10/Jun/20

Commented by 06122004 last updated on 10/Jun/20

x^3 −4x=15⇒x^3 −3x^2 +3x^2 −9x+5x−15=0⇒ ⇒(x−3)(x^2 +3x+5)=0⇒x^2 +3x=−5⇒ ⇒x(x+1)(x+2)(x+3)= =(x^2 +3x)(x^2 +3x+2)=(−5)∗(−3)=15 ∗Javob∗ 15 Abdullaxatov Jasurbek

$$\mathrm{x}^{\mathrm{3}} −\mathrm{4x}=\mathrm{15}\Rightarrow\mathrm{x}^{\mathrm{3}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{3x}^{\mathrm{2}} −\mathrm{9x}+\mathrm{5x}−\mathrm{15}=\mathrm{0}\Rightarrow \\ $$$$\Rightarrow\left(\mathrm{x}−\mathrm{3}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}+\mathrm{5}\right)=\mathrm{0}\Rightarrow\mathrm{x}^{\mathrm{2}} +\mathrm{3x}=−\mathrm{5}\Rightarrow \\ $$$$\Rightarrow\mathrm{x}\left(\mathrm{x}+\mathrm{1}\right)\left(\mathrm{x}+\mathrm{2}\right)\left(\mathrm{x}+\mathrm{3}\right)= \\ $$$$=\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}+\mathrm{2}\right)=\left(−\mathrm{5}\right)\ast\left(−\mathrm{3}\right)=\mathrm{15} \\ $$$$\ast\mathrm{Javob}\ast\:\mathrm{15} \\ $$$$\mathrm{Abdullaxatov}\:\mathrm{Jasurbek} \\ $$

Commented by bobhans last updated on 10/Jun/20

wrong. (x^2 +3x)(x^2 +3x+2) = 15 ∗bobhans∗

$$\mathrm{wrong}. \\ $$$$\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3x}+\mathrm{2}\right)\:=\:\mathrm{15} \\ $$$$\ast\mathrm{bobhans}\ast \\ $$

Commented by Lekhraj last updated on 11/Jun/20

correct

$${correct} \\ $$

Commented by Lekhraj last updated on 11/Jun/20

why?

$${why}? \\ $$

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