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Question Number 98004 by Ar Brandon last updated on 11/Jun/20
limn→∞[sin(n)+4n×3n2×n+1n2−4]
Commented by bobhans last updated on 11/Jun/20
limn→∞sinnn×limn→∞3.4nn×limn→∞n+1n2−4=0×∞×0=0[limn→∞3.4nn=3×limn→∞ln(4).4n1=∞]
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