Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 98020 by bobhans last updated on 11/Jun/20

What is the area of the region bounded  by x^2 +y^2  ≤ 9 ; x+y ≤ 3 and y ≤ x

$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{region}\:\mathrm{bounded} \\ $$$$\mathrm{by}\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \:\leqslant\:\mathrm{9}\:;\:\mathrm{x}+\mathrm{y}\:\leqslant\:\mathrm{3}\:\mathrm{and}\:\mathrm{y}\:\leqslant\:\mathrm{x}\: \\ $$

Answered by bemath last updated on 11/Jun/20

Commented by bobhans last updated on 11/Jun/20

very..==afdolll

$$\mathrm{very}..==\mathrm{afdolll} \\ $$

Commented by Rio Michael last updated on 11/Jun/20

yeah! i got it now. you are correct   A = ((27π + 18)/8) square units

$$\mathrm{yeah}!\:\mathrm{i}\:\mathrm{got}\:\mathrm{it}\:\mathrm{now}.\:\mathrm{you}\:\mathrm{are}\:\mathrm{correct} \\ $$$$\:{A}\:=\:\frac{\mathrm{27}\pi\:+\:\mathrm{18}}{\mathrm{8}}\:\mathrm{square}\:\mathrm{units} \\ $$

Commented by bobhans last updated on 11/Jun/20

Terms of Service

Privacy Policy

Contact: info@tinkutara.com