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Question Number 98030 by bemath last updated on 11/Jun/20

Commented by bobhans last updated on 11/Jun/20

(a) P(head and 4 ) = (1/8)  (b) P(head or 4) = (5/8)

$$\left(\mathrm{a}\right)\:\mathrm{P}\left(\mathrm{head}\:\mathrm{and}\:\mathrm{4}\:\right)\:=\:\frac{\mathrm{1}}{\mathrm{8}} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{P}\left(\mathrm{head}\:\mathrm{or}\:\mathrm{4}\right)\:=\:\frac{\mathrm{5}}{\mathrm{8}} \\ $$

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