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Question Number 98306 by me2love2math last updated on 12/Jun/20

Commented by me2love2math last updated on 12/Jun/20

$$precalculus....q1and2pls$$

Answered by Rio Michael last updated on 12/Jun/20

$$f\left(t\right)=-0.005(t-12)(t+3)(t+0.85),0⩽t⩽28$$$$\left(\mathrm{a}\right)f\left(7\right)=-0.005(7-12)(7+13)(7+0.85)=11.35\mathrm{grams}/\mathrm{hour}$$$$\mathcal{D}\mathrm{o}\mathrm{the}\mathrm{rest}\mathrm{fof}t=13\mathrm{h},t=17\mathrm{hours},t=26\mathrm{hours}.$$$$\left(\mathrm{b}\right)\mathrm{when}\mathrm{the}\mathrm{growth}\mathrm{rate}\mathrm{is}0,\mathrm{the}f\left(t\right)=0$$$$\iff -0.005(t-12)(t+3)(t+0.85)=0\Rightarrow t=12\mathrm{h}$$$$\mathrm{at}t=0,f\left(0\right)=-0.005(-12)\left(3\right)(0.85)=0.05$$$$\left(\mathrm{d}\right)f{}^{\prime }\left(t\right)>0\mathrm{and}f{}^{\prime }\left(t\right)<0$$

Answered by Rio Michael last updated on 12/Jun/20

$$\left(2\right)\mathrm{grams}\mathrm{from}\mathrm{each}\mathrm{substance}=\mathrm{\Sigma }\mathrm{total}{\mathrm{n}}^{\mathrm{o}}\mathrm{of}\mathrm{grams}-\mathrm{\Sigma }\mathrm{required}\mathrm{for}\mathrm{each}\mathrm{sub}$$$$$$

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