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Question Number 98320 by pranesh last updated on 13/Jun/20

Answered by bemath last updated on 13/Jun/20

$$\mathrm{s}=\frac{1}{1-\mathrm{y}}+\frac{\mathrm{x}}{1-\mathrm{y}}+\frac{{\mathrm{x}}^2}{1-\mathrm{y}}+\frac{{\mathrm{x}}^3}{1-\mathrm{y}}+$$$$...+\frac{{\mathrm{x}}^{\mathrm{n}}}{1-\mathrm{y}}+...=\frac{\frac{1}{1-\mathrm{x}}}{1-\mathrm{y}}$$$$=\frac{1}{(1-\mathrm{x})(1-\mathrm{y})};\mid \mathrm{x}\mid <1\mathrm{\&}\mid \mathrm{y}\mid <1$$

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