Question and Answers Forum

All Questions      Topic List

Arithmetic Questions

Previous in All Question      Next in All Question      

Previous in Arithmetic      Next in Arithmetic      

Question Number 9847 by 0942679167 last updated on 07/Jan/17

Commented by prakash jain last updated on 08/Jan/17

Can u please type the question  image is not readble.  Or use app like camscanner to  take the image

$$\mathrm{Can}\:\mathrm{u}\:\mathrm{please}\:\mathrm{type}\:\mathrm{the}\:\mathrm{question} \\ $$$$\mathrm{image}\:\mathrm{is}\:\mathrm{not}\:\mathrm{readble}. \\ $$$$\mathrm{Or}\:\mathrm{use}\:\mathrm{app}\:\mathrm{like}\:\mathrm{camscanner}\:\mathrm{to} \\ $$$$\mathrm{take}\:\mathrm{the}\:\mathrm{image} \\ $$

Commented by FilupSmith last updated on 09/Jan/17

For n≥2 where n∈N, determine the  largest possible value of the expression:  V_n =sin(x_1 )cos(x_2 )+sin(x_2 )cos(x_3 )+...+sin(x_n )cos(x_1 )  ∀n∈N^(≥2) :x_n ∈R

$$\mathrm{For}\:{n}\geqslant\mathrm{2}\:\mathrm{where}\:{n}\in\mathbb{N},\:\mathrm{determine}\:\mathrm{the} \\ $$$$\mathrm{largest}\:\mathrm{possible}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{expression}: \\ $$$${V}_{{n}} =\mathrm{sin}\left({x}_{\mathrm{1}} \right)\mathrm{cos}\left({x}_{\mathrm{2}} \right)+\mathrm{sin}\left({x}_{\mathrm{2}} \right)\mathrm{cos}\left({x}_{\mathrm{3}} \right)+...+\mathrm{sin}\left({x}_{{n}} \right)\mathrm{cos}\left({x}_{\mathrm{1}} \right) \\ $$$$\forall{n}\in\mathbb{N}^{\geqslant\mathrm{2}} :{x}_{{n}} \in\mathbb{R} \\ $$

Commented by FilupSmith last updated on 09/Jan/17

I believe:  V_n =sin(x_n )cos(x_1 )+Σ_(t=1) ^n sin(x_t )cos(x_(t+1) )

$$\mathrm{I}\:\mathrm{believe}: \\ $$$${V}_{{n}} =\mathrm{sin}\left({x}_{{n}} \right)\mathrm{cos}\left({x}_{\mathrm{1}} \right)+\underset{{t}=\mathrm{1}} {\overset{{n}} {\sum}}\mathrm{sin}\left({x}_{{t}} \right)\mathrm{cos}\left({x}_{{t}+\mathrm{1}} \right) \\ $$

Answered by mrW1 last updated on 19/Jan/17

max. =n×((√2)/2)×((√2)/2)=(n/2)

$${max}.\:={n}×\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}×\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}=\frac{{n}}{\mathrm{2}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com