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Question Number 98568 by aurpeyz last updated on 14/Jun/20

Commented by aurpeyz last updated on 14/Jun/20

$$\mathrm{pls}\mathrm{help}\mathrm{me}\mathrm{with}\mathrm{question}13.9$$

Answered by mr W last updated on 14/Jun/20

$$thicknesst=2.5mm$$$$diameterofholed=6mm$$$$shearstress=\frac{F}{\pi dt}=3.0\times {10}^{8}Pa=0.3\frac{KN}{{mm}^2}$$$$\Rightarrow F=0.3\times \pi \times 6\times 2.5=14.14KN$$$$$$$$iftheholeisasquare,then$$$$\Rightarrow F=0.3\times 4\times 6\times 2.5=18KN$$

Commented by aurpeyz last updated on 15/Jun/20

$$\mathrm{it}\mathrm{is}\mathrm{a}\mathrm{square}.\mathrm{thanks}\mathrm{sir}$$

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