Question and Answers Forum

All Questions      Topic List

Coordinate Geometry Questions

Previous in All Question      Next in All Question      

Previous in Coordinate Geometry      Next in Coordinate Geometry      

Question Number 9861 by Raja Naik last updated on 09/Jan/17

find  λ value in λ^2 −4λ−13=0

$$\mathrm{find}\:\:\lambda\:\mathrm{value}\:\mathrm{in}\:\lambda^{\mathrm{2}} −\mathrm{4}\lambda−\mathrm{13}=\mathrm{0} \\ $$

Answered by FilupSmith last updated on 09/Jan/17

λ=((4±(√(16+4(13))))/2)  λ=((4±(√(68)))/2)  λ=((4±2(√(17)))/2)  λ=2±(√(17))

$$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{16}+\mathrm{4}\left(\mathrm{13}\right)}}{\mathrm{2}} \\ $$$$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{68}}}{\mathrm{2}} \\ $$$$\lambda=\frac{\mathrm{4}\pm\mathrm{2}\sqrt{\mathrm{17}}}{\mathrm{2}} \\ $$$$\lambda=\mathrm{2}\pm\sqrt{\mathrm{17}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com